KinematicsHard
Question
Acceleration versus velocity graph of a particle moving in a straight from rest as shown in figure. The corresponding velocity - time graph would : -
Options
A.
B.
C.
D.
Solution
a = - kv + c [k > 0, c > 0]
dt ⇒ - 
ln (-kv + c) = t
⇒ kv = c - e-kt
dt ⇒ - ln (-kv + c) = t⇒ kv = c - e-kt
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