KinematicsHard
Question
Water drops fall from a tap on the floor, 5 m below, at regular intervals of time, the first drop strikes the floor when the sixth drop begins to fall. The height at which the fourth drop will be from ground, at the instant when the first drop strikes the ground is $\_\_\_\_$ m.
$$\left( g = 10\text{ }m/s^{2} \right) $$
Options
A.2.5
B.4.0
C.4.2
D.3.8
Solution
Time to reach ground $= \sqrt{\frac{2\text{ }h}{\text{ }g}} = \sqrt{\frac{2 \times 5}{10}} = 1sec$
Five drops per second
Time between each drop $= 0.2sec$.
Time of fall for $4^{\text{th~}}$ drop is $1 - 0.6 = 0.4sec$
Height fall of $4^{\text{th~}}$ drop is $= \frac{1}{2} \times 10 \times {0.4}^{2} = 0.8\text{ }m$
Height from ground $= 5 - 0.8 = 4.2\text{ }m$
Create a free account to view solution
View Solution FreeMore Kinematics Questions
A particle is moving in x - y plane at 2 m/s along x - axis. 2 seconds later, its velocity is 4 m/s in a direction makin...A particle is projected at angle 37o with the incline plane in upward direction with speed 10 m/s. The angle of incline ...The SI unit of the inductance, the henry can by written as...Which the following functions of A and B may be performed if A and B possess different dimensions...A particle at a height ′h′ from the ground is projected with an angle 30o from the horizontal, it strikes th...