KinematicsEasy
Question
A particle has an initial velocity of (3î + 4ĵ) m/s and a constant acceleration of (4î - 3ĵ) m/s2. Its speed after one second will be equal to : -
Options
A.0
B.10 m/s
C.5√2 m/s
D.25 m/s
Solution
= (3 + 4 × 1) î + (4 + (- 3) × 1) ĵ = 7î + ĵ|
| = 
= 5√2 m/sCreate a free account to view solution
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