NEET | 2017Gaseous StateEasy

Question

A gas is allowed to expand in a well insulated container against a constant external pressure of 2.5atm from an initial volume of 2.50 L to a final volume of 4.50L. The change in internal energy ∆U of the gas in joules will be:-

Options

A.

- 500J

B.

- 505 J

C.

+ 505 J

D.

1136.25 J

Solution

Work done in irreversible process
W = - Pext ∆U
= - 2.5 [4.5 - 2.5] = - 5 L atm
= - 5 ×101.3J = - 505 J
Since system is well insulated q = 0
By FLOT   ∆E = q + W
∆E = W = - 505 J  Option(2)

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