Laws of MotionHard
Question
Two blocks, each having mass M, rest on frictionless surfaces as shown in the figure. If the pulleys are light and frictionless, and M on the incline is allowed to move down, then the tension in the string will be :
Options
A.2/3 Mg sin θ
B.3/2 Mg sin θ
C.
D.2 Mg sin θ
Solution
Mg sinθ − T = Ma [Newton′s II law for block 1]
T = Ma [Newton′s II law for block 2]
By dividing both equations
2 T = Mg sinθ T =
Create a free account to view solution
View Solution FreeMore Laws of Motion Questions
Two fixed frictionless inclined plane making an angle 30oand 60o with the vertical are shown in the figure. Two block A ...Two blocks are in contact on a frictionless table. One has mass m and the other 2m. A force F is applied on 2m as shown ...A body of mass 8 kg is hanging from another body of mass 12 kg. The combination is being pulled by a string with an acce...A block of mass m = 2 kg is resting on a rough inclined plane of inclination 30o as show in figure. The coefficient of f...System is shown in figure and wedge is moving towards left with speed 2 m/s. Then velocity of the block B will be:...