Laws of MotionHard
Question
Two fixed frictionless inclined plane making an angle 30oand 60o with the vertical are shown in the figure. Two block A and B are placed on the two planes. What is the relative vertical acceleration of A with respect to B ?
Options
A.4.9 ms-2 in horizontal direction
B.9.8 ms-2 in vertical direction
C.zero
D.4.9 ms-2 in vertical direction
Solution
mg sin θ = ma
∴ a = g sin θ
where a is along the inclined plane
∴ vertical component of acceleration is g sin2 θ
∴ relative vertical acceleration of A with respect to B is
g[sin2 60 + sin2 30] =
= 4.9 m/s2 in vertical direction.
∴ a = g sin θ
where a is along the inclined plane
∴ vertical component of acceleration is g sin2 θ
∴ relative vertical acceleration of A with respect to B is
g[sin2 60 + sin2 30] =
= 4.9 m/s2 in vertical direction.Create a free account to view solution
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