Laws of MotionHard
Question
Two blocks are in contact on a frictionless table. One has mass m and the other 2m. A force F is applied on 2m as shown in the figure. Now the same force F is applied from the right on m. In the two cases respectively, the ratio of force of contact between the two blocks will be :
Options
A.same
B.1 : 2
C.2 : 1
D.1 : 3
Solution
F − N = 2 ma, [Newton′s II law for block A]
N = ma1 [Newton′s II law for block B]
N = 2 ma2 [Newtons II law for block A]
F − N = m2a [Newtons II law for block B]
⇒ N = 2F/3 so the ratio is 1 : 2
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