Laws of MotionHard
Question
Two blocks are in contact on a frictionless table. One has mass m and the other 2m. A force F is applied on 2m as shown in the figure. Now the same force F is applied from the right on m. In the two cases respectively, the ratio of force of contact between the two blocks will be :
Options
A.same
B.1 : 2
C.2 : 1
D.1 : 3
Solution
F − N = 2 ma, [Newton′s II law for block A]
N = ma1 [Newton′s II law for block B]
N = 2 ma2 [Newtons II law for block A]
F − N = m2a [Newtons II law for block B]
⇒ N = 2F/3 so the ratio is 1 : 2
Create a free account to view solution
View Solution FreeMore Laws of Motion Questions
A tennis ball is dropped on the floor from a height of 20 m. It rebounds to a height of 5 m. If the ball was in contact ...When a force of constant magnitude always act perpendicular to the motion of a particle then...A motorcylist is going on an overbridge of radius r maintaining a constant speed v. As the motorcyclist goes up on the o...In figure shown, both block are released from rest. The time to cross each other is...A man is at rest in the middle of a pond on perfectly smooth ice. He can get himself to the shore by making use of Newto...