Laws of MotionHard
Question
Two blocks are in contact on a frictionless table. One has mass m and the other 2m. A force F is applied on 2m as shown in the figure. Now the same force F is applied from the right on m. In the two cases respectively, the ratio of force of contact between the two blocks will be :
Options
A.same
B.1 : 2
C.2 : 1
D.1 : 3
Solution
F − N = 2 ma, [Newton′s II law for block A]
N = ma1 [Newton′s II law for block B]
N = 2 ma2 [Newtons II law for block A]
F − N = m2a [Newtons II law for block B]
⇒ N = 2F/3 so the ratio is 1 : 2
Create a free account to view solution
View Solution FreeMore Laws of Motion Questions
φ is the angle of the incline when a block of mass m just start slipping down. The distance covered by the block if...If you want to pile up sand onto a circular area of radius R. The greatest height of the sand pile that can be erected w...The length of a spring is α when a force of 4 N is applied on it and the length is β when 5 N force is applied...The rocket engine lift a rocket from the earth, beacause hot gases :...Circular motion a motor cyclist wants to drive on the vertical surface of a wooden ′well′ of radius 5m, with...