Laws of MotionHard
Question
A body of mass 8 kg is hanging from another body of mass 12 kg. The combination is being pulled by a string with an acceleration of 2.2 m s-2 The tension T1 and T2 will be respectively :
(use g = 9.8m/s2)
(use g = 9.8m/s2)
Options
A.200 N, 80 N
B.220 N, 90 N
C.240 N, 96 N
D.260 N, 96 N
Solution
T2 − 8g = 8a [ Newton′s II law for 8 kg block]
⇒ T2 = 8 × 2.2 + 8 × 9.8
= 96 N
T1 − 12 g − T2 = 12 a [ Newton′s II law for 12 kg block]
⇒ T1 = 12 × 2.2 + 12 × 9.8 + 96
T1 = 240 N
Create a free account to view solution
View Solution FreeMore Laws of Motion Questions
A block of mass 2 kg. is lying on a floor. The coefficient of static friction is 0.54. What will be value of frictional ...A block of mass m is at rest with respect to a lift when placed on inclined plane of inclination θ inside the lift....Three solids of mass m1, m2 and m3 are connected with weight less string in succession and are placed on a frictionless ...An object with a mass 10 kg moves at a constant velocity of 10 m/sec. A constant force then acts for 4 seconds on the ob...Two strings (A, B) having linear densities $\mu_{A} = 2 \times 10^{- 4}\text{ }kg/m$ and $\mu_{B} = 4 \times 10^{- 4}\te...