Atomic StructureMedium
Question
In Q. 12, the potential energy of the electron is :
Options
A.− 1.7 eV
B.− 3.4 eV
C.− 6.8 eV
D.− 13.4 eV
Solution
P.E = 2(T.E.)
= 2 (− 3.4 )
= − 6.8 eV
= 2 (− 3.4 )
= − 6.8 eV
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