NEET | 2017Wave motionHard

Question

The photoelectric threshold wavelength of silver is 3250 × 10-10m. The velocity of the electron ejected from a silver surface by ultraviolet light of wavelength 2536×10-10 m is :-
(Given h = 4.14 ×10-15 eVs and c = 3× 108 ms-1)

Options

A.

≈0.6×106ms-1

B.

≈61×103 ms-1

C.

≈0.3×106 ms-1

D.

≈6×105 ms-1

Solution

λ0=3250 A∘
λ=2536 A∘
12mv2 =hc1λ-1λ0
v=2hcm1λ-1λ0
= 1×12400×1.6×10-199.1×10-317142536×3250
= 0.6 ×106 m/s = 6 ×105 m/s

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