Chemical BondingHard
Question
A + 2B → C, the rate equation for this reaction is given as
Rate = K[A][B].
If the concentration of A is kept the same but that of B is doubled what will happen to the rate itself ?
Rate = K[A][B].
If the concentration of A is kept the same but that of B is doubled what will happen to the rate itself ?
Options
A.halved
B.the same
C.doubled
D.quadrupled
Solution
Rate is first order with respect to B. So it doubles on doubling concentration of B, while keeping oncentration of A as same.
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