Atomic StructureEasy
Question
A sample of a hydrate of barium chloride weighing 61 g was heated until all the water of hydration is removed. The dried sample weighed 52g. The formula of the hydrated salt is: (atomic mass, Ba = 137 amu, Cl = 35.5 amu)
Options
A.BaCl2 + H2O
B.BaCl2 + 4H2O
C.BaCl2 + 3H2O
D.BaCl2 + 2H2O
Solution
BaCl2.xH2O → BaCl2 + xH2O.
mH2O = 61 - 52 = 9g
⇒ nH2O =
mBaCl2 = 52 ⇒ nBaCl2 =
⇒ simplest formula =
= 1 : 2 ⇒ BaCl2.2H2O
mH2O = 61 - 52 = 9g
⇒ nH2O =
mBaCl2 = 52 ⇒ nBaCl2 =
⇒ simplest formula =
= 1 : 2 ⇒ BaCl2.2H2OCreate a free account to view solution
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