Atomic StructureHard

Question

The radii of two of the first four Bohr′s orbits of the hydrogen atom are in the ratio 1 : 4 The energy difference between them may be :

Options

A.Either 12.09 eV or 10.2 eV
B.Either 2.55 eV or 10.2 eV
C.Either 13.6 eV or 3.4 eV
D.Either 3.4 eV or 0.85 eV

Solution

    ∴      
Among the first four orbits n1 and n2 can be 1 and 2 or 2 and 4.
∴    Energy difference can be :
E2 → 1 = 10.2 eV          or    E4 → 2 = 2.55 eV.

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