Atomic StructureHard
Question
The radii of two of the first four Bohr′s orbits of the hydrogen atom are in the ratio 1 : 4 The energy difference between them may be :
Options
A.Either 12.09 eV or 10.2 eV
B.Either 2.55 eV or 10.2 eV
C.Either 13.6 eV or 3.4 eV
D.Either 3.4 eV or 0.85 eV
Solution
∴ 
Among the first four orbits n1 and n2 can be 1 and 2 or 2 and 4.
∴ Energy difference can be :
E2 → 1 = 10.2 eV or E4 → 2 = 2.55 eV.
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