JEE Advanced | 2013Momentum and CollisionHard
Question
A particle of mass m is projected from the ground with an initial speed u0 at an angle α with the horizontal. At the highest point of its trajectory, it makes a completely inelastic collision with another identical particle, which was thrown vertically upward from the ground with the same initial speed u0. The angle that the composite system makes with the horizontal immediately after the collision is :-
Options
A.

B.

C.

D.

Solution

Maximum height of first particle Hmax =

Speed of 2nd particle at height Hmax given as

⇒ vy = u0cos α
By Momentum Conseravtion


⇒ Angle with horizontal immediately after the collision

Create a free account to view solution
View Solution FreeMore Momentum and Collision Questions
A capillary tube (A) is dropped in water. Another identical tube (B) is dipped in a soap water solution. Which of the fo...Calculate the force required to separate the glass plate of area 10-2 m2 with a film of water 0.05 mm thick [surface ten...A gun fires a bullet of mass 50 g with a velocity of 30m/s. Due to this, the gun is pushed back with a velocity of 1m/s,...A bomb of mass 16 kg at rest explodes into two pieces of masses of 4 kg and 12 kg. The velocity of the 12 kg mass is 4 m...A massless inelastic thread passes over a small frictionless pulley. Two identical blocks A and B of mass m = 2 kg are a...