Momentum and CollisionHard

Question

A shell is fired from a cannon with a velocity v (m/s) at an angle with the horizontal direction. At the highest point in its path it explodes in to two peeves of equal mass. One of the pieces retraces its path to the cannon and the speed (m/s) of the other piece immediately after the explosion is :-

Options

A.3vcosθ
B.2vcosθ
C.vcosθ
D.vcosθ

Solution

COME : mv cos θ = (-v cos θ) + v′
⇒ v′ ⇒  v′ = 3v cos θ

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