Momentum and CollisionHard
Question
A ball collides elastically with a massive wall moving towards it with a velocity v. The collision occurs at a height of h above ground level and the velocity of the ball just before collision is 2v in horizontal direction as shown in figure. Then the distance from the foot of the wall and the point on the ground where the ball lands (at the instant the ball lands) is :
Options
A.v 
B.2v
C.3v
D.4v
Solution
For an elastic collision
Velocity of approach = velocity of seperation ⇒ relative velocity of ball w.r.t. wall = 3v
then the desired distance = 3v ×
(
time for the ball to travel ′h′ in vertical direction)
Velocity of approach = velocity of seperation ⇒ relative velocity of ball w.r.t. wall = 3v
then the desired distance = 3v ×
( time for the ball to travel ′h′ in vertical direction)Create a free account to view solution
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