Momentum and CollisionHard
Question
A ball collides elastically with a massive wall moving towards it with a velocity v. The collision occurs at a height of h above ground level and the velocity of the ball just before collision is 2v in horizontal direction as shown in figure. Then the distance from the foot of the wall and the point on the ground where the ball lands (at the instant the ball lands) is :
Options
A.v 
B.2v
C.3v
D.4v
Solution
For an elastic collision
Velocity of approach = velocity of seperation ⇒ relative velocity of ball w.r.t. wall = 3v
then the desired distance = 3v ×
(
time for the ball to travel ′h′ in vertical direction)
Velocity of approach = velocity of seperation ⇒ relative velocity of ball w.r.t. wall = 3v
then the desired distance = 3v ×
( time for the ball to travel ′h′ in vertical direction)Create a free account to view solution
View Solution FreeMore Momentum and Collision Questions
Three objects A, B and C are kept in a straight line on a frictionless horizontal surface. The object A moves towards B ...An object moving through air at a speed v. If the area of the object normal to the direction of velocity is A and assumi...A uniform metallic spherical shell is suspended from ceiling. it has two holes A ans B at top and bottom respective. Whi...Two bodies, A and B, collide as shown in figures a and b below:Circle the true statement:...A ball of mass 10 kg is moving with a velocity of 10 m/ s. it strikes another ball of mass 5kg, which is moving in the s...