General Organic ChemistryEasy
Question
In Carius method of estimation of halogens, 250 mg of an organic compound gave 141 mg of AgBr. The percentage of bromine in the compound is : (at. mass Ag = 108; Br = 80)
Options
A.48
B.60
C.24
D.36
Solution
Organic compound 
AgBr
=
Number of moles of AgBr = Number of moles of Br- =
∴ mass of Br =
× 10−3 × 80
∴ mass % of Br =
× 100
= 24
AgBr =
Number of moles of AgBr = Number of moles of Br- =
∴ mass of Br =
× 10−3 × 80∴ mass % of Br =
× 100 = 24
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