SolutionHard

Question

Isohydric solutions are the solutions having the same concentration of hydronium ion. If 0.2 M-HA solution is isohydric with 4 × 10−4 M-HCl solution, then Kb of A− is

Options

A.8 × 10−7
B.1.25 × 10−8
C.1.25 × 10−6
D.8 × 107

Solution

$\left( \sqrt{K_{a}.C} \right)_{HA} = \left\lbrack H^{+} \right\rbrack_{HCl}$

$\text{Or, }\sqrt{K_{a} \times 0.2} = 4 \times 10^{- 4} \Rightarrow K_{a} = 8 \times 10^{- 7} $$$\therefore K_{b}\text{ of }A^{-} = \frac{10^{- 14}}{8 \times 10^{- 7}} = 1.25 \times 10^{- 8}$$

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