Chemical BondingHard

Question

Select the correct option it is known that
K_sp(AgCl) > K_sp (AgBr) > K_sp (AgI)

Options

A.E^o_{I^-/AgI /Ag} > E^o_Br^-/AgBr/Ag > E^o_Cl^-/AgCl/Ag

B.E^o_{I^-/AgI /Ag} < E^o_Br^-/AgBr/Ag < E^o_Cl^-/AgCl/Ag

C.E^o_{Ag /AgI/I^-} = E^o_Ag/AgBr/_Br^- = E^o_Ag/AgCl/Cl^-

D.None of these

Solution

E^o_I^-/AgI/Ag = E^o_Ag⁺/Ag + log K_sp

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