Atomic StructureHard
Question
Two hydrogen atoms are in excited state with electrons residing in n = 2. First one is moving towards left and emits a photon of energy E1 towards right. Second one is moving towards left with same speed and emits a photon of energy E2 towards left. Taking recoil of nucleus into account during emission process
Options
A.E1 > E2
B.E1 < E2
C.E1 = E2
D.information insufficient
Solution
From momentum conservation, v′ > v″ Thus E2 > E1
Create a free account to view solution
View Solution FreeMore Atomic Structure Questions
The pressure exerted by an electromagnetic wave of intensity I (watt/m2) on a non-reflecting surface is :[c is the veloc...The wavelength of the first spectral line in the Balmer series of hydrogen atom is 6561 The wavelength of the second spe...A gas is compressed isothermally to half its initial volume. The same gas is compressed separately throughan adiabatic p...The angular momentum of an electron in the 2nd excited state of a Helium ion (He+) is...What is the amount of energy released by deuterium and tritium fusion ?...