NEETAtomic StructureHardBloom L3
Question
The electrical conductivity of a semiconductor increases when electromagnetic radiation of wavelength shorter than $2480 \text{ nm}$ is incident on it. The band gap (in eV) for the semiconductor is:
Options
A.$0.9 \text{ eV}$
B.$0.7 \text{ eV}$
C.$0.5 \text{ eV}$
D.$1.1 \text{ eV}$
Solution
{"given":"Maximum wavelength causing increased conductivity: $\\lambda_{\\max} = 2480 \\text{ nm} = 24800 \\text{ Å}$. The band gap energy equals the minimum photon energy required to excite electrons across the gap, i.e., the energy corresponding to $\\lambda_{\\max}$.","key_observation":"The photon energy formula $E = \\dfrac{12400}{\\lambda(\\text{Å})} \\text{ eV}$ gives the minimum energy (band gap) when the maximum wavelength is used.","option_analysis":[{"label":"(A)","text":"0.9 eV","verdict":"incorrect","explanation":"This would correspond to $\\lambda = 12400/0.9 \\approx 13778$ Å $\\approx 1378$ nm, not 2480 nm."},{"label":"(B)","text":"0.7 eV","verdict":"incorrect","explanation":"This would correspond to $\\lambda = 12400/0.7 \\approx 17714$ Å $\\approx 1771$ nm, not 2480 nm."},{"label":"(C)","text":"0.5 eV","verdict":"correct","explanation":"$$E = \\frac{12400}{24800} = 0.5 \\text{ eV}$$, which correctly matches $\\lambda_{\\max} = 2480 \\text{ nm} = 24800 \\text{ Å}$."},{"label":"(D)","text":"1.1 eV","verdict":"incorrect","explanation":"This would correspond to $\\lambda = 12400/1.1 \\approx 11273$ Å $\\approx 1127$ nm, not 2480 nm."}],"answer":"(C)","formula_steps":[]}
Create a free account to view solution
View Solution FreeMore Atomic Structure Questions
Two cylinders A and B fitted with pistons contain equal amounts of an ideal diatomic gas at 300 K. The piston of A is fr...238U has 92 protons and 238 nucleons. It decays by emitting an Alpha particle and becomes...If Alpha, Beta and Gamma rays same momentum, which has the longest wavelength...Suppose the charge of a proton and an electron differ slightly. One of them is – e, the other is (e + ∆e). If the...In each fission of 92U235 releases 200 MeV, how many fission must occur per second to pruduce power of kW ?...