Atomic StructureHard
Question
Highly energetic electrons are bombarded on a target of an element containing 30 neutrons. The ratio of radii of nucleus to that of Helium nucelus is 141/3. The atomic number of nucleus will be :-
Options
A.25
B.26
C.56
D.30
Solution
r ∝ A1/3
= (14)1/3 ⇒ A = 56
A = Z + N = 56 ⇒ Z = 56 - 30 = 26
= (14)1/3 ⇒ A = 56A = Z + N = 56 ⇒ Z = 56 - 30 = 26
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