KTGEasy
Question
CO2(O-C-O) is a triatomic gas. Mean kinetic energy of one gram gas will be (If N-Avogadro′s number, k-Boltzmann′s constant and molecular weight of CO2 = 44) :-
Options
A.(3 / 88) NkT
B.(5 / 88) NkT
C.(6 / 88) NkT
D.(7 / 88) NkT
Solution
Mean kinetic energy for μ mole gas = μ.
RT
E = μ
RT = 
NkT = 
NkT
=
NkT [As f = 7 and M = 44 for CO2]
RTE = μ
RT = NkT = NkT=
NkT [As f = 7 and M = 44 for CO2]Create a free account to view solution
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