KTGEasy
Question
The average translational energy and the rms speed of molecules in a sample of oxygen gas at 300 K are 6.21 × 10-21 J and 484 m/s respectively. The corresponding values at 600 K are nearly (assuming ideal gas behaviour)
Options
A.12.42 × 10-21 J, 968 m/s
B.8.78 × 10-21 J, 684 m/s
C.6.21 × 10-21 J, 968 m/s
D.12.42 × 10-21 J, 684 m/s
Solution
The average translation KE = 
kT which is directly proportional to T, while rms speed of molecules is given by
i.e., vrms 0 ∝ √T
When temperature of gas is increased from 300 K to 600 K (i.e., 2 times), the average translation KE will increase to 2 times and rms speed to √2 or 1.414 times.
∴ Average translational KE = 2 × 6.21 × 10-21 J
= 12.42 × 10-21 J
and vrms = (1.414) (484) m/s
684 m/s
kT which is directly proportional to T, while rms speed of molecules is given by i.e., vrms 0 ∝ √TWhen temperature of gas is increased from 300 K to 600 K (i.e., 2 times), the average translation KE will increase to 2 times and rms speed to √2 or 1.414 times.
∴ Average translational KE = 2 × 6.21 × 10-21 J
= 12.42 × 10-21 J
and vrms = (1.414) (484) m/s
684 m/sCreate a free account to view solution
View Solution FreeMore KTG Questions
In vanderwall′′s gas equation if pressure is increase to large extent than what will be effect on volume....The air density at Mount Everest is less than that at the sea level. It is found by mountaineers that for one trip lasti...1 mole of a gas with γ = 7 / 5 is mixed with 1 mole of a gas with γ = 5/ 3, then the value of γ for the r...If f be the total degrees of freedom of the molecules of gas then the ratio of the specific heats of gas is :-...The specific heat of an ideal gas depends on temperature is-...