ThermodynamicsHard
Question
A monoatomic ideal gas, initially at temperature T1, is enclosed in a cylinder fitted with a frictionless piston. The gas is allowed to expend adiabatically to a temperature T2 by releasing the piston suddenly. If L1 and L2 are lengths of the gas column before and after expansion respectively, then T1 / T2 is given by
Options
A.(L1 / L2)2/3
B.(L1 / L2)
C.(L2 / L1)
D.(L2 / L1)2/3
Solution
During adiabatic expansion, we know
TVγ-1 = constant
or T1V1γ-1 = T2V2γ-1
For noatomic gas, γ = 5 / 3
∴
[A = area of cross section of piston]
= (L2 / L1)2/3
TVγ-1 = constant
or T1V1γ-1 = T2V2γ-1
For noatomic gas, γ = 5 / 3
∴
[A = area of cross section of piston]
= (L2 / L1)2/3
Create a free account to view solution
View Solution FreeMore Thermodynamics Questions
Temperature of an ideal gas is 300 K. The change in temperature of the gas when its volume changes from V to 2V in the p...A system does 50 J of work under adiabatic condition. In this process :-...A system is taken along the paths A and B as shown. If the amounts of heat given in these processes are ᐃQA and &#...Tw identical containers A and B with frictionless pistons contains the same ideal gas at the same temperature and the sa...Three closed vessels A, B and C at the same temperature T and contain gases which obey the Maxwellian distribution of ve...