ThermodynamicsHard
Question
An ideal monoatomic gas is taken round the cycle ACBCA as shown in the p-V diagram (see figure). The work done during the cycle is
Options
A.pV
B.2pV
C.1/pV
D.zero
Solution
Work done in cyclic process = area between the cycle
= AB × BC = (2 p - p) × (2V - V ) = pV
∴ Correct option is (a).
= AB × BC = (2 p - p) × (2V - V ) = pV
∴ Correct option is (a).
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