AIPMT | 2014ThermodynamicsHard
Question
A monoatomic gas at a pressure P, having a volume V expands isothermally to a volume 2 V and then adiabatically to a volume 16 V. The final pressure ofthe gas is (take γ = 
)
)Options
A.64 P
B.32 P
C.
D.16 P
Solution
Step - 1 Isothermal Expansion
PV = P22V ⇒ P2 =
Step - 2 Adiabatic Expansion
P2V2γ = P3V3γ
⇒(2V)5/3 = P3(16V)5/3
⇒ P3 =
PV = P22V ⇒ P2 =
Step - 2 Adiabatic Expansion
P2V2γ = P3V3γ
⇒
(2V)5/3 = P3(16V)5/3⇒ P3 =
Create a free account to view solution
View Solution FreeMore Thermodynamics Questions
If one mole of a monoatomic gas (γ = 5 / 3 ) is mixed with one mole of a diatomic gas (γ = 7 / 5 ), the value ...To rigid boxes containing different ideal gases are placed on a table. Box A contains one mole are placed on a table. Bo...During an adiabatic process, the pressure of a gas is found to be proportional to the cube of its absolute temperature. ...The amount of work done in converting 1 gm ice at -10o C into steam at 100o C will be : -...Two moles of ideal helium gas are in a rubber balloon at 30oC. The balloon is fully expandable and can be assumed to req...