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Question
What is the OH- concentration of an aqueous solution of a substance whose pH = 3.2 :-
Options
A.10-3.8
B.10-3.2
C.10-10.8
D.10-10.2
Solution
pOH = 14 - pH = 14 - 3.2 = 10.8
-log[OH-] = 10.8 ⇒ [OH-] = 10-10.8
-log[OH-] = 10.8 ⇒ [OH-] = 10-10.8
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