SolutionHard

Question

Moles of K2SO4 to be dissolved in 12 mol water to lower its vapour pressure by 10 mmHg at a temperature at which vapour pressure of pure water is 50 mm is :

Options

A.3 mol
B.2 mol
C.1 mol
D.0.5 mol

Solution

Lowering of V.P. is colligative property
thus,  iK2SO4 = 1 + (y - 1)x = 1 + 2x = 3
∴    If 

n1 = 1

Create a free account to view solution

View Solution Free
Topic: Solution·Practice all Solution questions

More Solution Questions

Two beakers, one containing 20 ml of a 0.05 M aqueous solution of a non volatile, non electrolyte and the other, the sam...5 moles of liquid X and 10 moles of liquid Y make a solution having a vapour pressure of 70 torr. The vapour pressures o...A current of 2.6 ampere was passed through CuSO4 solution for 380 sec. The amount of Cu deposited is (at. wt. of Cu = 63...The degree of dissociation (α) of a weak electrolyte, Ax By is related to van′t Hoff factor (i) by the expres...Which one is not equal to zero for an ideal solution:-...