Mole ConceptHard
Question
A 5L vessel contains 2.8 g of N2. When heated to 1800 K, 30% molecules are dissociated into atoms.
Options
A.Total no. of moles in the container will be 0.13
B.Total no. of molecules in the container will be close to 0.421 × 1023.
C.Total no. of moles in the container will be 0.098.
D.All of these are correct.
Solution
(A) and (B) Explanation : 30% of molecule dissociated N2 → 2N
Amount of N2 left =
= 0.1 × 0.7 = 0.07
(in moles)
No. of moles of N atoms formed = 2 ×
× 0.1 = 0.06
(A) Total no . of moles = 0.07 + 0.06 = 0.13
(B) Total number of molecules = 0.07 × 6.023 × 1023 = 4.2 × 1022 molecule = 0.421 × 1023
∴ We have to calculate molecule of nitrogen not atoms.
Amount of N2 left =
= 0.1 × 0.7 = 0.07(in moles)
No. of moles of N atoms formed = 2 ×
× 0.1 = 0.06 (A) Total no . of moles = 0.07 + 0.06 = 0.13
(B) Total number of molecules = 0.07 × 6.023 × 1023 = 4.2 × 1022 molecule = 0.421 × 1023
∴ We have to calculate molecule of nitrogen not atoms.
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