ThermochemistryHard
Question
NH3(g) + 3Cl2(g) → NCl3(g) + 3HCl(g) ; ᐃH1
N2(g) + 3H2(g) → 2NH3(g) ; ᐃH2
H2(g) + Cl2(g) → 2HCl(g) ; ᐃH3
The heat of formation of NCl3(g) in the terms of ᐃH1, ᐃH2 and ᐃH3 is
N2(g) + 3H2(g) → 2NH3(g) ; ᐃH2
H2(g) + Cl2(g) → 2HCl(g) ; ᐃH3
The heat of formation of NCl3(g) in the terms of ᐃH1, ᐃH2 and ᐃH3 is
Options
A.ᐃHf = - ᐃH1 + 
ᐃH3
ᐃH3B.ᐃHf = ᐃH1 + ᐃH3
ᐃH3C.ᐃHf = ᐃH1 - ᐃH3
ᐃH3D.None
Solution
N2(g) + 
Cl2(g) → NCl3(g) ᐃH = - ᐃH1 +
ᐃH3Create a free account to view solution
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