ThermochemistryMedium

Question

Enthalpy of neutralization of the reaction between CH3COOH(aq) and NaOH(aq) is −13.2 kcal/eq and that of the reaction between H2SO4(aq) and KOH(aq) is −13.7 kcal/eq. The enthalpy of dissociation of CH3COOH(aq) is

Options

A.−0.5 kcal eq–1
B.+0.5 kcal eq–1
C.−26.9 kcal eq–1
D.+13.45 kcal eq–1

Solution

$\Delta H = ( - 13.2) - ( - 13.7) = + 0.5\text{ kcal/eq}$

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