ThermochemistryHard

Question

When 1 g equivalent of strong acid reacts with strong base, the heat released is 13.5 kcal. When 1 g equivalent H2A is completely neutralized against strong base, 13 kcal is released. When 1 g equivalent B(OH)2 is completely neutralized against strong acid, 10 kcal heat is released. What is the enthalpy change when 1 mole of H2A is completely neutralized by B(OH)2?

Options

A.−27 kcal
B.−10 kcal
C.−20 kcal
D.−19 kcal

Solution

For H2A, enthalpy of ionization = $2 \times (13.5 - 13) = 1$ kcal/mol

For B(OH)2, enthalpy of ionization = $2 \times (13.5 - 10) = 7$kcal/mol

∴ Required $\Delta H = 2 \times 13.5 - 1 - 7 = - 19\text{ kcal}$

Create a free account to view solution

View Solution Free
Topic: Thermochemistry·Practice all Thermochemistry questions

More Thermochemistry Questions

The potential energy diagram for a reaction R &nbsp → P is give below ᐃHo of the reaction corresponds to the...Enthalpy change for the reaction,4H(g) → 2H2 (g) is - 869.6 kJ The dissociation energy of H - H bond is...ᐃHfo(298K) of methanol is given by the chemical equation :...The heat of reaction for : C10H8(s) + 12O2(g) → 10CO2(g) + 4H2O(l) at constant volume is 1228.2 kcal at 25oC. The ...Reactions involving gold have been of particular interest to a chemist. Consider the following reactions.Au(OH)3 + 4HCl ...