ThermochemistryHard
Question
Given the following equations and ᐃHo values, determine the enthalpy of reaction at 298 K for the reaction :
C2H4 (g) + 6F2 (g) → 2CF4 (g) + 4HF (g)
H2 (g) + F2 (g)→ 2HF (g) ; ᐃHo1 = - 537 kJ
C (s) + 2F2 (g) → CF4 (g) ; ᐃHo2 = - 680 kJ
2C (s) + 2H2 (g) → C2H4 (g) ; ᐃHo3 = 52 kJ
C2H4 (g) + 6F2 (g) → 2CF4 (g) + 4HF (g)
H2 (g) + F2 (g)→ 2HF (g) ; ᐃHo1 = - 537 kJ
C (s) + 2F2 (g) → CF4 (g) ; ᐃHo2 = - 680 kJ
2C (s) + 2H2 (g) → C2H4 (g) ; ᐃHo3 = 52 kJ
Options
A.-1165
B.-2486
C.+1165
D.+2486
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