ThermochemistryMedium
Question
Given the following equations and ᐃHo values, determine the enthalpy of reaction at 298 K for the reaction :
C2H4 (g) + 6F2 (g) → 2CF4 (g) + 4HF (g)
H2 (g) + F2 (g)→ 2HF (g) ; ᐃHo1 = - 537 kJ
C (s) + 2F2 (g) → CF4 (g) ; ᐃHo2 = - 680 kJ
2C (s) + 2H2 (g) → C2H4 (g) ; ᐃHo3 = 52 kJ
C2H4 (g) + 6F2 (g) → 2CF4 (g) + 4HF (g)
H2 (g) + F2 (g)→ 2HF (g) ; ᐃHo1 = - 537 kJ
C (s) + 2F2 (g) → CF4 (g) ; ᐃHo2 = - 680 kJ
2C (s) + 2H2 (g) → C2H4 (g) ; ᐃHo3 = 52 kJ
Options
A.-1165
B.-2486
C.+1165
D.+2486
More Thermochemistry Questions
The enthalpy of neutralization of a strong monobasic acid by a strong monoacidic base is –13,700 cal. A certain monobasi...In an ice calorimeter, a chemical reaction is allowed to occur in thermal contact with an ice water mixture at 0oC. Any ...The enthalpy of neutralization of a strong acid by a strong base is −57.32 kJ mol–1. The enthalpy of formation of water ...Calculate the magnitude of resonance energy of CO2 from the following data (in kJ/mol).Bond energies: C=O = 539.0, O=O =...Use the following data to calculate the enthalpy of hydration for caesium iodide and caesium hydroxide, respectively.Com...