ThermochemistryHard
Question
Stearic acid [CH3(CH2)16CO2H] is a fatty acid. 1.0 g of stearic acid was burned in a bomb calorimeter. The bomb had a heat capacity of 652 J/oC. If the temperature of 500g water (c = 4.18 J/goC) rose from 25.0 to 39.3oC, how much heat was released when the stearic acid was burned ? [Given Cp (H2O) = 4.18 J/goC]
Options
A.39.21 kJ
B.29.91 kJ
C.108 kJ
D.9.32 kJ
Solution
-qreaction = qbomb + qwater
qreaction = (C(bomb) + (mwater × c)) ᐃT
= (652 + 500 × 4.18) × 14.3
= 39210 J or 39.21 kJ
qreaction = (C(bomb) + (mwater × c)) ᐃT
= (652 + 500 × 4.18) × 14.3
= 39210 J or 39.21 kJ
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