ThermochemistryHard

Question

A volume of 4.0 L of a mixture of ethane and methane gases on complete combustion at 300 K produced 6.0 L of carbon dioxide. Find out the amount of heat evolved on burning 1 L of gaseous mixture. The heats of combustion of ethylene and methane are −1573 and −890 kJ per mole, respectively, at 300 K.

Options

A.4926 kJ
B.50 kJ
C.1231.5 kJ
D.200 kJ

Solution

let C2H6 = xL, then CH4 = (4 – x)L

Volume of CO2 produced, 2x + (4 – x) = 6 ⇒ x = 2

∴ Total heat evolved $= \left( \frac{- 1}{2} \times 1573 + \frac{1}{2} \times 890 \right) \times \frac{1}{0.0821 \times 300} = 50\text{ kJ}$

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