Chemical EquilibriumHard

Question

In an evacuated rigid vessel of volume V litre, one mole of solid ammonium carbonate (NH2CONH4) is taken and the vessel is heated to T K. The equilibrium total pressure of gases is found to be P atm. The percentage dissociation of solid into NH3(g) and CO2(g) is

Options

A.$\frac{100RT}{3PV}\%$
B.$\frac{RT}{3PV}\%$
C.$\frac{100PV}{3RT}\%$
D.$\frac{300PV}{RT}\%$

Solution

NH2CONH4(s) $\rightleftharpoons$2NH3(g) + CO2(g)

Initial moles 1 0 0

Equ. moles 1 – $\alpha$ 2$\alpha$ $\alpha$

From question, $3\alpha = \frac{PV}{RT}$

∴ Percentage dissociation of solid = 100$\alpha$ %

$= \frac{100PV}{3RT}\%$

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