Chemical EquilibriumHard
Question
For the equilibrium SrCl2 · 6H2O(s) ⇋ SrCl2 · 2H2O(s) + 4H2O (g) the equilibrium constant KP = 16 × 10-12 atm4 at 1oC. If one litre of air saturated with water vapour at 1oC is exposed to a large quantity of SrCl2· 2H2O(s), what weight of water vapour will be absorbed? Saturated vapour pressure of water at 1oC = 7.6 torr.
Options
A.6.4 mg
B.3.25 mg
C.2.3 mg
D.8.5 mg
Solution
SrCI2 . 6H2O(s) ⇋ SrCI2 . 2H2O(s) + 4H2O(g) Kp = 16 × 10-12
(PH2O)4 = Kp PH2O = (KP)1/4 = 2 × 10-3 atm
H2O (l) ⇋ H2O(g) pH2O =
= 1.0 × 10-2
nH2O =
= 4.45 × 10-4
nH2O =
= 8.9 × 10-5 ∴ nH2O = absorbed = 3.56 × 10-4
∴ wt absorbed = 6.4 mg. Therefore, (A) option is correct.
(PH2O)4 = Kp PH2O = (KP)1/4 = 2 × 10-3 atm
H2O (l) ⇋ H2O(g) pH2O =
= 1.0 × 10-2nH2O =
= 4.45 × 10-4nH2O =
= 8.9 × 10-5 ∴ nH2O = absorbed = 3.56 × 10-4∴ wt absorbed = 6.4 mg. Therefore, (A) option is correct.
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