Chemical EquilibriumHard
Question
An equilibrium mixture in a vessel of capacity 100 litre contain 1 mol N2, 2 mol O2 and 3 mol NO. Number of moles of O2 to be added so that at new equilibrium the conc. of NO is found to be 0.04 mol/lit.:
Options
A.(101/18)
B.(101/9)
C.(202/9)
D.None of these
Solution
N2 (g) + O2 (g) 2NO (g)
1mole 2mole 3mole
KC =
.
Let a mole of O2 is added, Then,
N2 (g) + O2 (g) 2NO (g)
1mole 2mole 3mole
t = 0 1 (2 + a) 3
(1 -x) (2 + a)-x (3 + 2x)
[NO] =
= 0.04 ; (3 + 2x) = 4.
2x = 1, x = 0.5.
KC =
KC =
=
= [1.5 + a]
7.11 = 1.5 + a .
a =
= 5.61
1mole 2mole 3mole
KC =
.Let a mole of O2 is added, Then,
N2 (g) + O2 (g) 2NO (g)
1mole 2mole 3mole
t = 0 1 (2 + a) 3
(1 -x) (2 + a)-x (3 + 2x)
[NO] =
= 0.04 ; (3 + 2x) = 4.2x = 1, x = 0.5.
KC =
KC =
=
= [1.5 + a]7.11 = 1.5 + a .
a =
= 5.61Create a free account to view solution
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