Chemical EquilibriumHard
Question
For the reaction H2(g) + I2(g) $\rightleftharpoons$2HI(g), the value of equilibrium constant is 9.0. The degree of dissociation of HI will be
Options
A.0.5
B.0.33
C.0.4
D.0.67
Solution
$K = \frac{\frac{\alpha}{2}.\frac{\alpha}{2}}{(1 - \alpha)^{2}} = \frac{1}{9} \Rightarrow \alpha = 0.4$
Create a free account to view solution
View Solution FreeMore Chemical Equilibrium Questions
The standard emf of cell, involving one electron change is found to be 0.591 V at 25ºC. The equilibrium constant of the ...The following equilibria are given : N2 + 3H2 ⇋ 2NH3 K1 N2 + O2 ⇋ 2NO K2 H2 + O2 ⇋ H2O K3 The equilibr...Consider the following liquid - vapour equilibrium. Liquid ⇌ Vapour Which of the following relations is correct?...For the reaction 2NOCl(g)$\rightleftharpoons$ 2NO(g) + Cl2(g), ΔHo = 18 kcal and ΔSo = 30 cal/K at 300 K. The equilibriu...Consider the general reaction given below at 400 K$$xA(g) \rightleftharpoons yB(g) $$The values of $K_{p}$ and $K_{c}$ a...