Chemical EquilibriumMedium
Question
For the reaction H2(g) + I2(g) $\rightleftharpoons$2HI(g), the value of equilibrium constant is 9.0. The degree of dissociation of HI will be
Options
A.0.5
B.0.33
C.0.4
D.0.67
Solution
$K = \frac{\frac{\alpha}{2}.\frac{\alpha}{2}}{(1 - \alpha)^{2}} = \frac{1}{9} \Rightarrow \alpha = 0.4$
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