Chemical EquilibriumHard
Question
Sulfide ion in alkaline solution reacts with solid sulfur to form polysulfide ions having formulae S22-, S32-, S42- and so on. The equilibrium constant for the formation of S22- is 12 (K1) & for the formation of S32- is 132 (K2), both from S and S2-. What is the equilibrium constant for the formation of S32- from S22- and S ?
Options
A.11
B.12
C.132
D.None of these
Solution
S (s) + S2- (aq) ⇋ S22- (aq) K1 = 12
2S (s) + S2- (aq) ⇋ S32- (aq) K2 = 132
Now , S22- (aq) + S (s) S32- (aq) Keq =
= 11
2S (s) + S2- (aq) ⇋ S32- (aq) K2 = 132
Now , S22- (aq) + S (s) S32- (aq) Keq =
Create a free account to view solution
View Solution FreeMore Chemical Equilibrium Questions
The following equilibrium are given CO + H2O ⇋ CO2 + H2 ----- K12H2 + O2 ⇋ 2H2O ------ K2then equilibrium co...For the equilibrium, A(g) B(g), ⇋H is −40 kJ/mol. If the ratio of the activation energies of the forward(Ef)...The reactions PCl5(g) ⇋ PCl3(g) + Cl2(g) and COCl2(g) ⇋ CO(g) + Cl2(g) are simultaneously in equilibrium at ...In the reaction C(s) + CO2(g) ⇋ 2CO(g), the equilibrium pressure is 12 atm. If 50% of CO2 reacts then Kp will be :...The equilibrium $\text{SO}_2\text{Cl}_2(g) \rightleftharpoons \text{SO}_2(g) + \text{Cl}_2(g)$ is attained at $25^\circ\...