Chemical EquilibriumHard

Question

Sulfide ion in alkaline solution reacts with solid sulfur to form polysulfide ions having formulae S22-, S32-, S42- and so on. The equilibrium constant for the formation of S22- is 12 (K1) & for the formation of S32- is 132 (K2), both from S and S2-. What is the equilibrium constant for the formation of S32- from S22- and S ?

Options

A.11
B.12
C.132
D.None of these

Solution

S (s) + S2- (aq) ⇋ S22- (aq)        K1 = 12
2S (s) + S2- (aq) ⇋ S32- (aq)        K2 = 132
Now ,    S22- (aq) + S (s)  S32- (aq)        Keq = = 11

Create a free account to view solution

View Solution Free
Topic: Chemical Equilibrium·Practice all Chemical Equilibrium questions

More Chemical Equilibrium Questions

To convert PhH → Ph3C - CO2H the sequence of reagent added will be :...The rate constant for the forward reaction: A(g)$\rightleftharpoons$ 2B(g) is 1.5 × 10−3 s−1 at 300 K. If 10−5 moles of ...Pure ammonia is placed in a vessel at a temperature where its dissociation constant (α) is appreciable. At equilibr...PCl5(g) $\rightleftharpoons$PCl3(g) + Cl2(g). In the above reaction, the partial pressure of PCl3, Cl2 and PCl5 are 0.3,...Some quantity of water is contained in a container as shown in figure. As neon is added to this system at constant press...