Chemical EquilibriumHard
Question
Sulfide ion in alkaline solution reacts with solid sulfur to form polysulfide ions having formulae S22-, S32-, S42- and so on. The equilibrium constant for the formation of S22- is 12 (K1) & for the formation of S32- is 132 (K2), both from S and S2-. What is the equilibrium constant for the formation of S32- from S22- and S ?
Options
A.11
B.12
C.132
D.None of these
Solution
S (s) + S2- (aq) ⇋ S22- (aq) K1 = 12
2S (s) + S2- (aq) ⇋ S32- (aq) K2 = 132
Now , S22- (aq) + S (s) S32- (aq) Keq =
= 11
2S (s) + S2- (aq) ⇋ S32- (aq) K2 = 132
Now , S22- (aq) + S (s) S32- (aq) Keq =
Create a free account to view solution
View Solution FreeMore Chemical Equilibrium Questions
At –10oC, the solid compound Cl2(H2O)8 is in equilibrium with gaseous chlorine, water vapour and ice. The partial pressu...Find the concentration of manomeric dichloroacetic acid in a CCl4 solution which contains 0.0129 g of the acid in 100 ml...The equilibrium constant for reaction H2(g) + CO2(g) ⇋ H2O(g) + CO(g) is 1·8 at 1000oC. If one mole of H2 and 1·0 ...The activation energies for the forward and reverse elementary reactions in the system A$\rightleftharpoons$B are 10.303...In the decomposition equilibrium of a certain alkaline earth metal carbonate, the partial pressure of CO2 becomes a hund...