Chemical EquilibriumHard
Question
Sulfide ion in alkaline solution reacts with solid sulfur to form polysulfide ions having formulae S22-, S32-, S42- and so on. The equilibrium constant for the formation of S22- is 12 (K1) & for the formation of S32- is 132 (K2), both from S and S2-. What is the equilibrium constant for the formation of S32- from S22- and S ?
Options
A.11
B.12
C.132
D.None of these
Solution
S (s) + S2- (aq) ⇋ S22- (aq) K1 = 12
2S (s) + S2- (aq) ⇋ S32- (aq) K2 = 132
Now , S22- (aq) + S (s) S32- (aq) Keq =
= 11
2S (s) + S2- (aq) ⇋ S32- (aq) K2 = 132
Now , S22- (aq) + S (s) S32- (aq) Keq =
Create a free account to view solution
View Solution FreeMore Chemical Equilibrium Questions
The following reaction has an equilibrium constant KC equal to 3.07 × 10–4 at 24°C....For the reaction 3 A (g) + B ⇋ (g) 2 C (g) at a given temperature, Kc = 9.0. What must be the volume of the flask,...In a flask, colourless N2O4 is in equilibrium with brown coloured NO2. At equilibrium, when the flask is heated at 100oC...For a reversible reaction A + B$\rightleftharpoons$C, if the concentrations of the reactants are doubled at a definite t...For dissociation of a gas N2O5 as N2O5(g) $\rightleftharpoons$2NO2(g) + ½ O2(g). The reaction is performed at constant t...