Chemical EquilibriumHard
Question
The equilibrium constant Kp1 and Kp2 for the reactions A ⇋ 2B and P ⇋ Q + R, respectively, are in the ratio of 2 : 3. If the degree of dissociation of A and P are equal, the total pressure at equilibrium is,
Options
A.1 : 36
B.1 : 9
C.1 : 6
D.1 : 4
Solution
For A ⇋ 2B
Initial 1 0
At equilibrium 1 - α 2α
Total moles = 1 - α + 2α = 1 + α
∴ PA = (mole fraction of A) × Initial pressure =
Similarly PB =
KP1 =
For P ⇋ Q + R
Initial 1 0 0
At equilibrium 1 - α α α
Total moles = 1 - α + α + α = 1 + α
∴ PP =
P2 ; PQ = 
P2; PR = 
P2
KP2 =
∴
(given) = 
∴
Initial 1 0
At equilibrium 1 - α 2α
Total moles = 1 - α + 2α = 1 + α
∴ PA = (mole fraction of A) × Initial pressure =
Similarly PB =
KP1 =
For P ⇋ Q + R
Initial 1 0 0
At equilibrium 1 - α α α
Total moles = 1 - α + α + α = 1 + α
∴ PP =
P2 ; PQ = P2; PR = P2 KP2 =
∴
(given) = ∴
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