Chemical EquilibriumHard
Question
For a reaction,
A → B ; if log10 K(sec-1) = 14 -
the Arrheniums parameter and energy of activation for the reaction are :
A → B ; if log10 K(sec-1) = 14 -
the Arrheniums parameter and energy of activation for the reaction are :Options
A.1014 sec-1, 239.34 kJ
B.14,57.6 kcal
C.1014 sec-1, 23.93 kJ
D.1014 sec, 5.76 kcal
Solution
2.303 log10 K = 2.303 log10 A = 
∴
= 1.25 × 104
∴ Ea = 1.25 × 104 × 2.303 × 8.314
239.34 × 103 J
log A = 14 ∴ A = 1 × 1014
∴
= 1.25 × 104∴ Ea = 1.25 × 104 × 2.303 × 8.314
239.34 × 103 J
log A = 14 ∴ A = 1 × 1014
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