SolutionHard
Question
A solution containing 28 g of phosphorus in 315 g CS2 (b.p. 46.3oC) boils at 47.98oC. If Kb for CS2 is 2.34 K kg mol-1. The formula of phosphorus is (at. mass of P = 31).
Options
A.P6
B.P4
C.P3
D.P2
Solution
ᐃTb = m Kb = 
× Kb
ᐃTb = 47.98 - 46.3 = 1.68
1.68 =
× 2.28
M =
= 125.92
Atomicity =
= 4.02
So. Molecule is = P4 .
× KbᐃTb = 47.98 - 46.3 = 1.68
1.68 =
× 2.28M =
= 125.92Atomicity =
= 4.02So. Molecule is = P4 .
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