SolutionHard
Question
Elevation in b.p. of an aqueous urea solution is 0.52o. (Kb = 0.52o mol-1 kg) Hence, mole-fraction of urea in this solution is :
Options
A.0.982
B.0.567
C.0.943
D.0.018
Solution
As ᐃTb = molality × Kb
0.52 = m × 0.52
molality = 1 mol kg-1
∴ urea = 1 mol
moles of water =
= 55.55
mole fraction of urea =
= 0.018
0.52 = m × 0.52
molality = 1 mol kg-1
∴ urea = 1 mol
moles of water =
= 55.55mole fraction of urea =
= 0.018Create a free account to view solution
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