SolutionHard
Question
The vapour pressure of water at room temperature is lowered by 5% by dissolving a solute in it, then the approximate molality of solution is :
Options
A.2
B.1
C.4
D.3
Solution
Where XB = mole fraction of solute.
Molality =
Create a free account to view solution
View Solution FreeMore Solution Questions
Relative decrease in vapour pressure of an aqueous NaCl is 0.167. Number of moles of NaCl present in 180g of H2O is :...Y gm of non-volatile organic substance of molecular mass M is dissolved in 250 gm benzene. Molal elevation constant of b...Equimolar solutions in the same solvent have...A liquid solution is formed by mixing 10 moles of aniline and 20 moles of phenol at a temperature where the vapour press...At 298 K , the mole percentage of $N_{2}(\text{ }g)$ in air is $80\%$. Water is in equilibrium with air at a pressure of...