SolutionHard

Question

The vapour pressure of water at room temperature is lowered by 5% by dissolving a solute in it, then the approximate molality of solution is :

Options

A.2
B.1
C.4
D.3

Solution

= 0.05 = XB
Where XB = mole fraction of solute.
Molality = = 1000 × 0.05 / 0.95 × 18 = 2.92 ≈ 3.0

Create a free account to view solution

View Solution Free
Topic: Solution·Practice all Solution questions

More Solution Questions

A solution is prepared by dissolving 0.3 g of a nonvolatile non-electrolyte solute ' A ' of molar mass $60\text{ }g{\tex...When only a little quantity of HgCl2(s) is added to excess KI(aq) to obtain a clear solution, which of the following is ...Select correct statement(s) :...For which of the following pair, the heat of mixing, ΔHmix, is approximately zero?...Vapour density of PCl5 (g) dissociating into PCl3(g) and Cl2(g) is 100. Hence, van′t Hoff factor for the case : PC...