SolutionHard
Question
For a dilute solution containing 2.5 g of a non-volatile non-electrolyte solute in 100 g of water, the elevation in boiling point at 1 atm pressure is 2oC. Assuming concentration of solute is much lower than theconcentration of solvent, the vapour pressure (mm of Hg) of the solution is (take Kb = 0.76 K kg mol-1)
Options
A.724
B.740
C.736
D.718
Solution
B → Solute; A → Solvent
WB = 2.5 g, WA = 100 g
ᐃTb = 2o
∴ nB ≪ nA
....(i)
and from boiling point elevation,
2 = 0.76 × m
....(ii)
on equating (i) and (ii)
Psoln = 724 mm
WB = 2.5 g, WA = 100 g
ᐃTb = 2o
∴ nB ≪ nA ....(i)and from boiling point elevation,
2 = 0.76 × m
....(ii)on equating (i) and (ii)
Psoln = 724 mm
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