SolutionHard
Question
Osmotic pressure of 30% solution of glucose is 1.20 atm and that of 3.42% solution of cane sugar is 2.5 atm. The osmotic pressure of the mixture containing equal volumes of the two solutions will be
Options
A.2.5 atm
B.3.7 atm
C.1.85 atm
D.1.3 atm.
Solution
πfVf = π1V1 + π2V2
πf =
πf = 1.85 atm.
πf =
πf = 1.85 atm.
Create a free account to view solution
View Solution FreeMore Solution Questions
A quantity of 2 g of C6H5COOH dissolved in 25 g of benzene shows a depression in freezing point equal to 1.96 K. Molar d...On the electrolysis of 10-8 M HCl solution :- (a) O2 gas is produced at anode (b) Cl2 gas is produced at anode (c) H2 ga...At 298 K , the mole percentage of $N_{2}(\text{ }g)$ in air is $80\%$. Water is in equilibrium with air at a pressure of...Air was drawn through a solution containing 40 g of solute (non-volatile and non-electrolyte) in 100 g of water and then...Conductivity (unit Siemen′s S) is directly proportional to area of the vessel and the concentration of the solutio...