SolutionHard
Question
A solution of a substance containing 1.05 g per 100 mL. was found to be isotonic with 3% glucose solution. The molecular mass of the substance is :
Options
A.31.5
B.6.3
C.630
D.63
Solution
For isotonic solution π1 = π2 ; C1 = C2 ; n1 = n2
⇒ 
⇒ M = 
= 63 Ans.
⇒ ⇒ M = = 63 Ans.Create a free account to view solution
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