SolutionHard
Question
A complex containing K+, Pt(IV) and Cl- is 100% ionised giving i = 3. Thus, complex is :
Options
A.K2[PtCl4]
B.K2[PtCl6]
C.K3[PtCl5]
D.K[PtCl3]
Solution
i = van′t Hoff factor = 1 + (y - 1) x
i = van′t Hoff factor = 1 + (y - 1) x
(y = number of ions, x = degree of ionisation)
y i = 1 + (y -1) x
(a) K2PtCl4 2K+ + PtCl42- 3 1 + 2 = 3
(b) K2PtCl6 2K+ + PtCl62- 3 3
In (a), oxidation number of Pt = 2
In (b) oxidation number of Pt = 4
i = van′t Hoff factor = 1 + (y - 1) x
(y = number of ions, x = degree of ionisation)
y i = 1 + (y -1) x
(a) K2PtCl4 2K+ + PtCl42- 3 1 + 2 = 3
(b) K2PtCl6 2K+ + PtCl62- 3 3
In (a), oxidation number of Pt = 2
In (b) oxidation number of Pt = 4
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